21=3*x^2

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Solution for 21=3*x^2 equation:



21=3x^2
We move all terms to the left:
21-(3x^2)=0
a = -3; b = 0; c = +21;
Δ = b2-4ac
Δ = 02-4·(-3)·21
Δ = 252
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{252}=\sqrt{36*7}=\sqrt{36}*\sqrt{7}=6\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{7}}{2*-3}=\frac{0-6\sqrt{7}}{-6} =-\frac{6\sqrt{7}}{-6} =-\frac{\sqrt{7}}{-1} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{7}}{2*-3}=\frac{0+6\sqrt{7}}{-6} =\frac{6\sqrt{7}}{-6} =\frac{\sqrt{7}}{-1} $

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